1. Which of these has the largest value?
- A25
- B52
- C33
- D42
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Answer: A. 25 = 32, 52 = 25, 33 = 27 and 42 = 16. The largest is 25.
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Practise O Level / IGCSE Mathematics (4024 / 0580) with 576 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
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Practise O Level / IGCSE Mathematics (4024 / 0580) with 576 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
576 questions · 9 chapters
The questions follow the syllabus chapter by chapter. You can test the whole subject or one chapter at a time.
12 questions from the test, one or two from each chapter. Try each one, then open the answer.
Answer: A. 25 = 32, 52 = 25, 33 = 27 and 42 = 16. The largest is 25.
Answer: B. Acceleration = gradient = change in speed ÷ time = (16 − 4) ÷ 6 = 2 m/s2. Using 16 ÷ 6 ignores the starting speed.
Answer: D. The fourth vertex is directly above (1, 2) and level with (5, 6), so it is (1, 6). x-coordinate first, then y.
Answer: D. The square is the base and the four triangles fold up to meet at the apex: a square-based pyramid. A tetrahedron has four triangular faces and no square.
Answer: B. The diagonals cross at right angles and split the rhombus into 4 right-angled triangles with legs 5 cm and 8 cm: 4 × ½ × 5 × 8 = 80 cm2. This equals ½ × 10 × 16. Forgetting the ½ gives 160.
Answer: D. The height bisects the base into 4 cm and 4 cm: h = √(82 − 42) = √48 = 6.93 cm. Adding the squares gives √80 = 8.94.
Answer: D. From the centre (1, 1) to (5, 7) is 4 across and 6 up. Halve these: 2 across and 3 up from the centre gives (3, 4). Halving the coordinates themselves only works when the centre is the origin.
Answer: C. On a tree diagram there are two branches: late then not late (0.2 × 0.8) and not late then late (0.8 × 0.2). Total 0.16 + 0.16 = 0.32. Counting only one branch gives 0.16.
Answer: D. The gradient is (65 − 25) ÷ (30 − 10) = 2, so from (10, 25) a rise of 10 in x adds 20: y = 25 + 20 = 45.
Answer: A. The integers greater than −2 and up to and including 3 are −1, 0, 1, 2, 3, so n(A) = 5. −2 is not included because of the strict <.
Answer: C. From the second equation y = 3x − 3. Substitute: 2x + 3(3x − 3) = 13, so 11x − 9 = 13 and x = 2, then y = 3. Always check in both equations: x = 5, y = 1 fits the first but not the second.
Answer: D. Same gradient 1/2, so y = x/2 + c. Substitute (4, −1): −1 = 2 + c, so c = −3. Equation y = x/2 − 3.
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