1. Given that log2 x = 5, find x.
- A32
- B10
- C25
- D2.5
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Answer: A. log2 x = 5 means 25 = x, so x = 32.
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Practise IB Maths: Analysis and Approaches (SL / HL) with 282 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
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Practise IB Maths: Analysis and Approaches (SL / HL) with 282 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
282 questions · 5 chapters
The questions follow the syllabus chapter by chapter. You can test the whole subject or one chapter at a time.
12 questions from the test, one or two from each chapter. Try each one, then open the answer.
Answer: A. log2 x = 5 means 25 = x, so x = 32.
Answer: C. At x = 0 the line (2) is above the curve (1), but for large positive or negative x the curve is above the line, so they cross twice (at about x = −1.84 and x = 1.15, as a GDC confirms).
Answer: D. Cone = (1/3)π(9)(4) = 12π and hemisphere = (2/3)π(27) = 18π, total 30π cm3. Using a full sphere gives 48π.
Answer: D. P(RB) + P(BR) = (5/8)(3/7) + (3/8)(5/7) = 30/56 = 15/28. Both orders count, and the second draw is out of 7.
Answer: D. At x = 1, y = 4 and dy/dx = 2x + 3 = 5. y − 4 = 5(x − 1) gives y = 5x − 1. y = −⅕x + 4.2 is the normal.
Answer: B. Start from one side and transform it into the other: LHS = n2 + 2n + 1 − n2 + 2n − 1 = 4n = RHS. Starting from the result you want to prove assumes it is true.
Answer: C. 20 = 80e−10k gives e−10k = 1/4, so 10k = ln 4 and k = (ln 4)/10 ≈ 0.139. The minus sign is already in the model, so k is positive.
Answer: C. Arc = 10 × 0.8 = 8 cm, and the perimeter also includes two radii: 8 + 10 + 10 = 28 cm.
Answer: A. The probabilities must sum to 1: 0.1 + 0.3 + k + 0.2 = 1, so k = 0.4.
Answer: D. f(x) = x3 − 2x + C, and f(1) = 1 − 2 + C = 4 gives C = 5.
Answer: B. (a + b)n has n + 1 terms, so power 5 needs six coefficients: 1, 5, 10, 10, 5, 1.
Answer: B. Vertical asymptote where the denominator is zero: x = 3. Horizontal asymptote y = a/c = 2/1 = 2, since for large x the constants hardly matter.
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282 MCQs with answers, covering 5 chapters of the syllabus. Each test draws new questions, so you can practise many times.
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