1. A set A has 128 subsets. The number of elements in A is
- A64
- B7
- C8
- D6
Show answer
Answer: B. A set with n elements has 2n subsets, and 27 = 128, so n = 7. Halving 128 to get 64 confuses subsets with elements.
Free tests
Video courses
Study notes
Account
Practise NUST NET Maths (Engineering) with 219 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
Loading the test…
Practise NUST NET Maths (Engineering) with 219 exam-style MCQs, each with the answer and a short explanation. Every test is marked the moment you finish and shows your score chapter by chapter, so you know what to revise next. It is free and needs no sign-up.
219 questions · 11 chapters
The questions follow the syllabus chapter by chapter. You can test the whole subject or one chapter at a time.
12 questions from the test, one or two from each chapter. Try each one, then open the answer.
Answer: B. A set with n elements has 2n subsets, and 27 = 128, so n = 7. Halving 128 to get 64 confuses subsets with elements.
Answer: A. The third row is 2 times the first row. A determinant with two proportional rows is 0, so no expansion is needed.
Answer: B. Replace x by 1/x and clear fractions: 2 + 5x − 3x2 = 0, i.e. 3x2 − 5x − 2 = 0. Check: the original roots are 1/2 and −3, and (3x + 1)(x − 2) = 0 gives 2 and −1/3.
Answer: D. Put x = 1: the sum of the coefficients is (3 − 2)5 = 1. Adding 3 and 2 instead gives 55 = 3125.
Answer: A. Treat the pair as one unit: 7 units round a table in (7 − 1)! = 720 ways, and the pair can swap seats in 2 ways, giving 1440. Forgetting the swap gives 720.
Answer: C. Factorise: (sin2θ − cos2θ)(sin2θ + cos2θ) = sin2θ − cos2θ = −(cos2θ − sin2θ) = −cos 2θ.
Answer: D. f(x) = −1 for x < 0 and f(x) = 1 for x > 0, so the limit at 0 does not exist. f(0) = 0 is defined, but that alone does not make f continuous.
Answer: C. Take logs: ln y = x ln x, so (1/y) dy/dx = ln x + 1 and dy/dx = xx(1 + ln x). The power rule and the ax rule each give only part of this.
Answer: A. d/dx ln|2x + 1| = 2/(2x + 1), so divide by 2: the integral is (1/2) ln|2x + 1| + c.
Answer: A. √[(5 + 1)2 + (−6 − 2)2] = √(36 + 64) = √100 = 10. Adding the coordinates instead of subtracting them gives 4√2.
Answer: D. cos2 α + cos2 β + cos2 γ = 1 gives 1/4 + 1/4 + cos2 γ = 1, so cos γ = 1/√2 and γ = 45°.
Answer: B. (2 − i)2 = 4 − 4i + i2 = 3 − 4i, and the conjugate changes only the sign of the imaginary part: 3 + 4i. The option 3 − 4i is the square itself, not its conjugate.
When you get a question wrong, a short note called "The idea behind this" explains the topic it belongs to, with the rules to remember and a worked example.
Yes. Every test and every explanation is free, and you do not need an account. If you sign in, your results are kept across your devices.
The 219 MCQs are our own, written to the syllabus in the style of the exam.
Instantly. You get your score, the right answer and an explanation for every question, and a list of the topics to work on.