A swimmer dives to a depth of 4.0 m in a lake. The density of the water is 1000 kg/m3, g = 9.8 N/kg and atmospheric pressure is 100 000 Pa. What is the total pressure on the swimmer?
- Pressure due to the water: Δp = ρgΔh = 1000 × 9.8 × 4.0 = 39 200 Pa
- The atmosphere presses on the surface of the lake, so add it: 100 000 + 39 200
- Total pressure = 139 200 Pa
Answer: 139 200 Pa (about 1.4 × 105 Pa).