Carboxylic acids have the general formula CnH2n+1COOH. For the acid with n = 2, find the structural formula, the molecular formula and Mr. (H 1, C 12, O 16)
- Put n = 2: C2H5COOH, which is CH3CH2COOH.
- Count the atoms: 3 C, 6 H and 2 O, so the molecular formula is C3H6O2.
- Mr = (3 × 12) + (6 × 1) + (2 × 16) = 36 + 6 + 32 = 74.
Answer: CH3CH2COOH (propanoic acid), molecular formula C3H6O2, Mr = 74.