Calcium oxide removes sulfur dioxide from flue gases: CaO + SO2 → CaSO3. What mass of calcium oxide is needed to remove 6.4 kg of sulfur dioxide? (O 16, S 32, Ca 40)
- Mr of SO2 = 32 + (2 × 16) = 64; Mr of CaO = 40 + 16 = 56.
- 1 mol of CaO reacts with 1 mol of SO2, so 64 g of SO2 needs 56 g of CaO.
- Mass of CaO = 6.4 × 56 ÷ 64 = 5.6 kg.
Answer: 5.6 kg of calcium oxide.