Water (density 1000 kg m−3) flows at 2.0 m s−1 through a horizontal pipe of diameter 4.0 cm, which narrows to a diameter of 2.0 cm. By how much does the pressure fall in the narrow part?
- Half the diameter gives a quarter of the area, so v2 = 4 × 2.0 = 8.0 m s−1.
- P1 − P2 = ½ρ(v22 − v12) = ½ × 1000 × (64 − 4).
- = 500 × 60 = 30 000 Pa.
Answer: 3.0 × 104 Pa