NUST NET (Engineering) key facts
Every chapter of NUST NET (Engineering) on one page: the 313 key facts, definitions and facts to remember, in syllabus order. Use it for a last look before a test, then check yourself.
Maths · Numbers, sets and functions
Complex numbers
- i2 = −1, i3 = −i, i4 = 1; for in, divide n by 4 and use the remainder as the new power
- Any four consecutive powers of i add up to 0
- Conjugate of z = a + bi is z̄ = a − bi; z + z̄ = 2a, z − z̄ = 2bi, z × z̄ = a2 + b2
- To divide, multiply top and bottom by the conjugate of the bottom
- Modulus: |z| = √(a2 + b2)
- |z1z2| = |z1| × |z2| and |z1/z2| = |z1| ÷ |z2|, so a modulus can be found without simplifying first
- Argument θ: tan θ = b/a, with the quadrant taken from the signs of a and b; principal value −π < θ ≤ π
Sets and functions
- n(A ∪ B) = n(A) + n(B) − n(A ∩ B)
- A set with n elements has 2n subsets, of which 2n − 1 are proper subsets
- De Morgan's laws: (A ∪ B)′ = A′ ∩ B′ and (A ∩ B)′ = A′ ∪ B′
- Domain: denominator ≠ 0; expression under a square root ≥ 0 (strictly > 0 if the root is in a denominator)
- (f∘g)(x) = f(g(x)): work out g first, then put the result into f
- Inverse: write y = f(x), swap x and y, solve for y; domain of f−1 = range of f
- Even: f(−x) = f(x). Odd: f(−x) = −f(x), so an odd function defined at 0 has f(0) = 0
Maths · Matrices and determinants
Matrices and determinants
- (m × n)(n × p) gives an m × p matrix; the inner numbers must match
- For A with rows [a b] and [c d]: |A| = ad − bc, and A−1 = (1/|A|) × the matrix with rows [d −b] and [−c a]
- (AB)−1 = B−1A−1 and (AB)t = BtAt (the order reverses)
- |At| = |A|, |AB| = |A| × |B|, |A−1| = 1/|A|, and |kA| = kn|A| for an n × n matrix
- A determinant is 0 if a row is all zeros or two rows (or columns) are equal or proportional; swapping two rows changes its sign
- AX = B: if |A| ≠ 0 there is one solution, X = A−1B; if |A| = 0 there is either no solution (inconsistent) or infinitely many
- Homogeneous system AX = O: only x = y = z = 0 if |A| ≠ 0; non-trivial solutions if |A| = 0
Maths · Quadratic equations
Quadratic equations
- x = (−b ± √(b2 − 4ac))/(2a)
- b2 − 4ac > 0: real and distinct roots; = 0: real and equal; < 0: complex conjugate roots
- With rational a, b, c: the roots are rational when b2 − 4ac is a perfect square, irrational when it is positive but not a perfect square
- Sum of roots α + β = −b/a; product αβ = c/a
- Equation with given roots: x2 − (sum of roots)x + (product of roots) = 0
- α2 + β2 = (α + β)2 − 2αβ; (α − β)2 = (α + β)2 − 4αβ; α3 + β3 = (α + β)3 − 3αβ(α + β)
- Cube roots of unity: 1 + ω + ω2 = 0 and ω3 = 1, so reduce any power of ω using its remainder on division by 3
Maths · Sequences, series and the binomial theorem
Sequences and series
- Arithmetic: Tn = a + (n − 1)d; Sn = (n/2)[2a + (n − 1)d] = (n/2)(a + l), where l is the last term
- Geometric: Tn = arn − 1; Sn = a(1 − rn)/(1 − r), r ≠ 1
- Sum to infinity: S∞ = a/(1 − r), only for |r| < 1
- From a sum formula: Tn = Sn − Sn − 1
- Between a and b: arithmetic mean A = (a + b)/2; geometric mean G = ±√(ab); harmonic mean H = 2ab/(a + b)
- G2 = A × H; for two different positive numbers A > G > H, taking G as the positive root
- In a geometric sequence, Tm ÷ Tn = rm − n; in an arithmetic sequence, Tm − Tn = (m − n)d
Binomial theorem and partial fractions
- General term of (a + b)n: Tr + 1 = nCr an − r br
- Middle term: T(n/2) + 1 if n is even; two middle terms T(n + 1)/2 and T(n + 3)/2 if n is odd
- Sum of the coefficients of an expansion: put x = 1; sum of the binomial coefficients of (1 + x)n is 2n
- Series: (1 + x)n = 1 + nx + n(n − 1)x2/2! + n(n − 1)(n − 2)x3/3! + ..., valid for |x| < 1; for small x, (1 + x)n ≈ 1 + nx
- (a + bx)n = an(1 + bx/a)n, valid for |bx/a| < 1, that is |x| < |a/b|
- Partial fraction forms: (x − a) gives A/(x − a); (x − a)2 gives A/(x − a) + B/(x − a)2; a quadratic that will not factorise gives (Ax + B)/(that quadratic)
- If the degree of the top is not lower than the bottom, divide first; for a non-repeated factor (x − a), find A by covering that factor and putting x = a in the rest
Maths · Permutations, combinations and probability
Permutations and combinations
- n! = n × (n − 1) × ... × 2 × 1, and 0! = 1
- nPr = n!/(n − r)! (order matters)
- nCr = n!/(r! × (n − r)!) (order does not matter); nCr = nCn − r
- nPr = r! × nCr
- n objects with p alike of one kind and q alike of another: n!/(p! × q!) arrangements
- n different objects round a circle: (n − 1)! arrangements
- Together: treat the group as one object, then multiply by the arrangements inside it. Apart: arrange the others first, then fill the gaps
Probability
- P(A) = number of favourable outcomes ÷ total number of outcomes; 0 ≤ P(A) ≤ 1
- P(A′) = 1 − P(A)
- P(A ∪ B) = P(A) + P(B) − P(A ∩ B); for mutually exclusive events P(A ∩ B) = 0
- Independent events: P(A ∩ B) = P(A) × P(B)
- Without replacement: P(A then B) = P(A) × P(B after A has happened)
- P(at least one) = 1 − P(none); P(neither A nor B) = 1 − P(A ∪ B)
- Sample sizes: two dice 36; n coins 2n; a pack has 52 cards, 26 red, 13 in each suit, 12 face cards
Maths · Trigonometry
Trigonometric ratios and identities
- π radians = 180°: multiply degrees by π/180 to get radians, and radians by 180/π to get degrees
- Arc length l = rθ; area of sector A = ½r2θ (θ in radians)
- sin2θ + cos2θ = 1; 1 + tan2θ = sec2θ; 1 + cot2θ = cosec2θ
- sin(α ± β) = sin α cos β ± cos α sin β; cos(α ± β) = cos α cos β ∓ sin α sin β
- tan(α ± β) = (tan α ± tan β)/(1 ∓ tan α tan β)
- sin 2θ = 2 sin θ cos θ; cos 2θ = cos2θ − sin2θ = 2cos2θ − 1 = 1 − 2sin2θ; tan 2θ = 2 tan θ/(1 − tan2θ)
- Half angle: sin2(θ/2) = (1 − cos θ)/2; cos2(θ/2) = (1 + cos θ)/2; tan(θ/2) = sin θ/(1 + cos θ)
Trigonometric graphs, triangles and equations
- Period: sin, cos, sec, cosec 2π; tan, cot π. For sin kx or cos kx the period is 2π/|k|; for tan kx it is π/|k|
- Range: sin x and cos x lie in [−1, 1], so a + b sin x lies in [a − |b|, a + |b|]; tan x takes all real values
- Sine rule: a/sin α = b/sin β = c/sin γ = 2R (R = circum-radius)
- Cosine rule: a2 = b2 + c2 − 2bc cos α, or cos α = (b2 + c2 − a2)/(2bc)
- Area Δ = ½bc sin α = √(s(s − a)(s − b)(s − c)) with s = (a + b + c)/2; in-radius r = Δ/s; circum-radius R = abc/(4Δ)
- Principal ranges: sin−1x in [−π/2, π/2]; cos−1x in [0, π]; tan−1x in (−π/2, π/2)
- General solutions (n ∈ Z): sin x = sin α gives x = nπ + (−1)nα; cos x = cos α gives x = 2nπ ± α; tan x = tan α gives x = nπ + α
Maths · Functions and limits
Limits and continuity
- limx→0 (sin x)/x = 1 and limx→0 (tan x)/x = 1, with x in radians; so limx→0 (sin ax)/(bx) = a/b
- limx→0 (1 − cos ax)/x2 = a2/2
- limn→∞ (1 + 1/n)n = e, and in general limn→∞ (1 + a/n)bn = eab
- limx→0 (ax − 1)/x = ln a, so limx→0 (ex − 1)/x = 1
- limx→a (xn − an)/(x − a) = n an−1
- As x→∞ in a fraction of polynomials, divide by the highest power of x; equal degrees give the ratio of the leading coefficients
- f is continuous at x = a when the left-hand limit = the right-hand limit = f(a)
Maths · Differentiation
Rules of differentiation
- Product: (uv)′ = u′v + uv′. Quotient: (u/v)′ = (u′v − uv′)/v2. Chain: dy/dx = (dy/du) × (du/dx)
- Derivatives: sin x → cos x, cos x → −sin x, tan x → sec2 x, cot x → −cosec2 x, sec x → sec x tan x, cosec x → −cosec x cot x
- eax → a eax; ax → ax ln a; ln x → 1/x; ln f(x) → f′(x)/f(x)
- sin−1 x → 1/√(1 − x2); cos−1 x → −1/√(1 − x2); tan−1 x → 1/(1 + x2)
- Implicit f(x, y) = 0: dy/dx = −(derivative of f treating y as constant) ÷ (derivative of f treating x as constant)
- Parametric: dy/dx = (dy/dt) ÷ (dx/dt), and d2y/dx2 = [d/dt (dy/dx)] ÷ (dx/dt)
- nth derivative of eax is an eax; of sin ax it is an sin(ax + nπ/2)
Applications of derivatives
- Tangent at (a, b): y − b = m(x − a) with m = f′(a); the normal has gradient −1/m
- f′(x) > 0: increasing. f′(x) < 0: decreasing. f′(x) = 0: stationary point
- At a stationary point: f″ < 0 gives a maximum, f″ > 0 gives a minimum; if f″ = 0, check the sign change of f′
- Related rates: dy/dt = (dy/dx) × (dx/dt), for example dV/dt = 4πr2 × (dr/dt) for a sphere
- Small increments: δy ≈ f′(x) × δx, so f(x + δx) ≈ f(x) + f′(x) δx
- Motion: velocity v = ds/dt, acceleration a = dv/dt = d2s/dt2
- Two positive numbers with a fixed sum have the greatest product when they are equal; with a fixed product they have the least sum when they are equal
Maths · Integration
Methods of integration
- ∫ xn dx = xn+1/(n + 1) + c for n ≠ −1; ∫ (1/x) dx = ln|x| + c
- Linear inside: ∫ f(ax + b) dx = (1/a) F(ax + b) + c, e.g. ∫ cos(ax) dx = (1/a) sin(ax) + c
- ∫ f′(x)/f(x) dx = ln|f(x)| + c; ∫ [f(x)]n f′(x) dx = [f(x)]n+1/(n + 1) + c
- ∫ dx/(a2 + x2) = (1/a) tan−1(x/a) + c; ∫ dx/√(a2 − x2) = sin−1(x/a) + c
- By parts: ∫ u dv = uv − ∫ v du; choose u in the order logarithm, inverse trig, algebraic, trig, exponential
- ∫ ex[f(x) + f′(x)] dx = ex f(x) + c
- ∫ dx/(x2 − a2) = (1/(2a)) ln|(x − a)/(x + a)| + c; ∫ tan x dx = ln|sec x| + c; ∫ cot x dx = ln|sin x| + c
Definite integrals and areas
- ∫ab f(x) dx = F(b) − F(a), where F′(x) = f(x)
- ∫ba f dx = −∫ab f dx, and ∫ab f dx = ∫ac f dx + ∫cb f dx
- ∫−aa f dx = 0 if f is odd, and = 2 ∫0a f dx if f is even
- ∫0a f(x) dx = ∫0a f(a − x) dx; hence ∫0π/2 sin2 x dx = ∫0π/2 cos2 x dx = π/4
- Area between two curves = ∫ (upper − lower) dx between the points where they meet
- Shortcut: the area between a parabola y = ax2 + bx + c and a straight line (or the x-axis) that meet at x = α and x = β is |a|(β − α)3/6
- Separable equation: write g(y) dy = f(x) dx and integrate both sides with one constant; dy/dx = ky gives y = Aekx
Maths · Analytic geometry
Straight lines
- Distance = √[(x2 − x1)2 + (y2 − y1)2]; midpoint = ((x1 + x2)/2, (y1 + y2)/2)
- Point dividing AB internally in m : n is ((mx2 + nx1)/(m + n), (my2 + ny1)/(m + n)); for external division replace n by −n
- Gradient m = (y2 − y1)/(x2 − x1) = tan θ; the line ax + by + c = 0 has gradient −a/b
- Forms of a line: y − y1 = m(x − x1); y = mx + c; x/a + y/b = 1 (intercepts a and b)
- Parallel: m1 = m2. Perpendicular: m1 × m2 = −1
- Acute angle between two lines: tan θ = |(m1 − m2)/(1 + m1m2)|
- Distance from (x1, y1) to ax + by + c = 0 is |ax1 + by1 + c|/√(a2 + b2); between parallel lines with the same a and b it is |c1 − c2|/√(a2 + b2)
Circles and conic sections
- Circle (x − h)2 + (y − k)2 = r2: centre (h, k), radius r
- Circle x2 + y2 + 2gx + 2fy + c = 0: centre (−g, −f), radius √(g2 + f2 − c); make the coefficients of x2 and y2 equal to 1 first
- Tangent to x2 + y2 = r2 at (x1, y1): xx1 + yy1 = r2; the line y = mx + c touches this circle when c2 = r2(1 + m2)
- Parabola y2 = 4ax: vertex (0, 0), focus (a, 0), directrix x = −a. Parabola x2 = 4ay: focus (0, a), directrix y = −a
- Ellipse x2/a2 + y2/b2 = 1 with a > b: c2 = a2 − b2, e = c/a, foci (±c, 0), directrices x = ±a2/c
- If the larger number is under y2, the major axis is along the y-axis and the foci are (0, ±c)
- Hyperbola x2/a2 − y2/b2 = 1: c2 = a2 + b2, e = c/a, foci (±c, 0), directrices x = ±a2/c
Linear inequalities and linear programming
- Boundary line: solid for ≤ or ≥ (points on the line included), broken for < or > (points on the line excluded)
- Test (0, 0) in the inequality: if it is true, the solution is the side containing the origin; if false, the other side. Use another point if the line passes through the origin
- Feasible region = the part of the plane common to all the constraints
- Corner points are where two boundary lines meet; solve the pair of equations, then check the point satisfies every other constraint
- The maximum and minimum of z = ax + by over a closed and bounded feasible region occur at corner points: evaluate z at each corner and compare
- If two neighbouring corners give the same best value, every point on the edge joining them is also optimal
Maths · Vectors
Vectors in space
- |a| = √(a12 + a22 + a32); unit vector = a/|a|
- Direction cosines: l = a1/|a|, m = a2/|a|, n = a3/|a|, and l2 + m2 + n2 = 1
- a · b = a1b1 + a2b2 + a3b3 = |a||b| cos θ; the vectors are perpendicular when a · b = 0
- Projection of a on b = (a · b)/|b|; work done = F · d
- a × b = (a2b3 − a3b2)i − (a1b3 − a3b1)j + (a1b2 − a2b1)k; |a × b| = |a||b| sin θ; a × b = −b × a
- Area of a parallelogram = |a × b|; area of a triangle = (1/2)|a × b|
- a · (b × c) = the 3 × 3 determinant of the components; volume of a parallelepiped = its size; the vectors are coplanar when it is 0
Physics · Measurement, vectors and equilibrium
Measurement
- Prefixes: giga 109, mega 106, kilo 103, centi 10−2, milli 10−3, micro 10−6, nano 10−9, pico 10−12
- Force [MLT−2]; work, energy and torque [ML2T−2]; power [ML2T−3]; pressure [ML−1T−2]
- Momentum and impulse [MLT−1]; angular momentum and Planck's constant [ML2T−1]
- Pure numbers, angles, sin θ, logs and constants such as 2π have no dimensions
- Adding or subtracting quantities: add the absolute uncertainties
- Multiplying or dividing quantities: add the percentage uncertainties; for a power xn, multiply the percentage uncertainty in x by n
- Significant figures: zeros at the front do not count (0.0320 has three); zeros between digits, and zeros at the end after a decimal point, do count
Vectors and equilibrium
- Components: Ax = A cos θ, Ay = A sin θ (θ measured from the x-axis); A = √(Ax2 + Ay2), tan θ = Ay/Ax
- Resultant of A and B with angle θ between them: R = √(A2 + B2 + 2AB cos θ); largest A + B, smallest |A − B| (the difference of the magnitudes)
- Scalar product: A · B = AB cos θ = AxBx + AyBy + AzBz; i · i = 1, i · j = 0
- Vector product: |A × B| = AB sin θ = area of the parallelogram on A and B (the triangle is half of it)
- i × j = k, j × k = i, k × i = j; reversing the order changes the sign: A × B = −(B × A)
- Torque τ = r × F, size rF sin θ = force × perpendicular distance from the pivot (N m)
- Equilibrium: sum of forces = 0 and sum of torques = 0 (clockwise moments = anticlockwise moments)
Physics · Mechanics
Motion and force
- v = u + at; s = ut + ½at2; v2 = u2 + 2as; s = ½(u + v)t
- From rest with constant acceleration, distance ∝ t2; stopping distance = u2/(2a)
- F = ma; impulse = FΔt = change in momentum (N s = kg m s−1)
- Collisions: m1u1 + m2u2 = m1v1 + m2v2; if the bodies stick, v = m1u1/(m1 + m2) for a target at rest
- Elastic head-on, target at rest: v1 = (m1 − m2)u/(m1 + m2), v2 = 2m1u/(m1 + m2)
- Two masses over a smooth pulley: a = (m1 − m2)g/(m1 + m2)
- Projectile: time of flight T = 2u sin θ/g; greatest height H = u2 sin2θ/(2g); range R = u2 sin 2θ/g, greatest at 45°
Work, energy and power
- work = force × distance × cos θ (W = Fd cos θ), in joules
- Variable force: work = area under the force-displacement graph
- kinetic energy = ½mv2 = p2/(2m), so momentum p = √(2m × KE)
- gravitational potential energy = mgh; energy stored in a spring = ½kx2
- Falling from rest through height h with no friction: v = √(2gh), whatever the mass or the path
- power = work ÷ time = force × velocity (P = Fv), in watts; 1 kW h = 3.6 × 106 J
- Net work done = change in kinetic energy; work against friction = friction force × distance
Circular and rotational motion
- ω = 2π/T = 2πf; v = rω; 1 revolution = 2π rad
- Centripetal acceleration a = v2/r = rω2; centripetal force F = mv2/r = mrω2
- String in a vertical circle: tension = mv2/r + mg at the bottom, mv2/r − mg at the top
- Moment of inertia: hoop MR2; disc ½MR2; solid sphere (2/5)MR2; thin rod about its centre (1/12)ML2; torque τ = Iα
- Angular momentum L = Iω = mvr (kg m2 s−1 = J s); with no external torque I1ω1 = I2ω2
- Rotational KE = ½Iω2; rolling body: total KE = ½mv2 + ½Iω2 (hoop mv2, disc ¾mv2, solid sphere (7/10)mv2)
- Orbit of radius r: v = √(GM/r), T2 ∝ r3; close to the Earth v = √(gR) ≈ 7.9 km s−1 and T = 2π√(R/g) ≈ 84 min
Fluid dynamics
- Coefficient of viscosity η: unit N s m−2 = Pa s = kg m−1 s−1; dimensions [ML−1T−1]
- Stokes' law: drag F = 6πηrv, for a small sphere moving slowly in streamline flow
- Terminal velocity vt = 2gr2ρ/(9η) (ρ = density of the sphere, upthrust ignored), so vt ∝ r2
- Continuity: A1v1 = A2v2; volume flow rate = Av (m3 s−1)
- Bernoulli: P + ½ρv2 + ρgh = constant along a streamline
- Horizontal flow: P1 − P2 = ½ρ(v22 − v12)
- Torricelli: speed of water leaving a hole a depth h below the surface, v = √(2gh)
Physics · Oscillations, waves and light
Oscillations
- a = −ω2x; ω = 2πf = 2π/T
- Mass on a spring: T = 2π√(m/k); for a load that stretches the spring by e, T = 2π√(e/g)
- Simple pendulum: T = 2π√(l/g), independent of the mass of the bob; a seconds pendulum has T = 2 s
- Starting from the mean position: x = x0 sin ωt; v = ω√(x02 − x2)
- Maximum speed = ωx0 (at the centre); maximum acceleration = ω2x0 (at the ends)
- Total energy = ½kx02 = ½mω2x02; PE = ½kx2; KE = ½k(x02 − x2)
- KE = PE when x = x0/√2; resonance when driving frequency = natural frequency
Waves and sound
- v = fλ; speed of a wave on a string v = √(T/μ), T = tension, μ = mass per unit length
- String fixed at both ends, or pipe open at both ends: fn = nv/(2L), n = 1, 2, 3 … (all harmonics)
- Pipe closed at one end: fn = nv/(4L), n = 1, 3, 5 … (odd harmonics only)
- Distance from node to next node = λ/2; from node to nearest antinode = λ/4
- Speed of sound in a gas ∝ √(absolute temperature); in air about 332 m s−1 at 0 °C, rising about 0.61 m s−1 per °C
- Beat frequency = f1 − f2 (the difference); time between beats = 1 ÷ beat frequency
- Doppler: f′ = f(v ± vo)/(v ∓ vs); upper signs when moving towards each other (vo listener, vs source)
Physical optics and optical instruments
- Young's double slit: fringe spacing = λL/d (d = slit separation, L = distance to screen)
- Bright fringe m at y = mλL/d (path difference mλ); dark fringe at y = (m + ½)λL/d
- Diffraction grating: d sin θ = nλ, with d = 1/N (N = lines per metre); highest order n ≤ d/λ
- Unpolarised light through an ideal polariser: intensity falls to half; two crossed polarisers pass nothing
- Simple magnifier: M = 1 + d/f (d = 25 cm); compound microscope: M = Mobjective × Meyepiece
- Astronomical telescope in normal adjustment: M = fo/fe, length = fo + fe
- Smallest angle resolved by a lens of diameter D: αmin = 1.22λ/D (radians); grating resolving power λ/Δλ = N × m (here N = total number of lines lit, m = order)
Physics · Heat and thermodynamics
Kinetic theory and thermodynamics
- PV = nRT = NkT; R = 8.31 J mol−1 K−1, k = 1.38 × 10−23 J K−1
- Pressure P = (1/3)ρ⟨v2⟩; mean translational KE per molecule = (3/2)kT
- vrms = √(3RT/M) = √(3kT/m): proportional to √T and to 1/√(molar mass)
- First law: Q = ΔU + W, where W = PΔV is the work done by the gas at constant pressure
- Constant volume: W = 0, Q = ΔU. Isothermal: ΔU = 0, Q = W. Adiabatic: Q = 0, W = −ΔU
- Cp − Cv = R; γ = Cp/Cv; monatomic Cv = 3R/2, γ = 5/3; diatomic Cv = 5R/2, γ = 7/5
- Efficiency = W/Q1 = 1 − Q2/Q1; Carnot engine: 1 − T2/T1 (T1 source, T2 sink, in kelvin)
Physics · Electricity
Electrostatics
- Coulomb's law: force = k × q1 × q2 ÷ r2 (F = kq1q2/r2), with k = 9 × 109 N m2 C−2
- Electric field = force ÷ charge (E = F/q); for a point charge E = kq/r2, unit N C−1 or V m−1
- Potential of a point charge: V = kq/r, in volts; keep the sign of q
- Uniform field between parallel plates: E = V/d
- Capacitance = charge ÷ potential difference (C = Q/V); parallel plates: C = ε0εrA/d
- Parallel: C = C1 + C2. Series: 1/C = 1/C1 + 1/C2, so for two capacitors C = C1C2/(C1 + C2)
- Energy stored = ½CV2 = ½QV = Q2/(2C)
Current electricity
- Resistance = resistivity × length ÷ area (R = ρL/A); resistivity ρ is in Ω m
- Temperature: Rt = R0(1 + αt), so α = (Rt − R0)/(R0 × t), unit K−1
- Series: R = R1 + R2. Parallel: 1/R = 1/R1 + 1/R2, so for two resistors R = R1R2/(R1 + R2)
- Cell with internal resistance r: I = E/(R + r) and terminal p.d. V = E − Ir
- Power = VI = I2R = V2/R; a cell gives maximum power to the load when R = r, and then P = E2/(4r)
- Kirchhoff: current into a junction = current out; round any closed loop, sum of EMFs = sum of IR drops
- Wheatstone bridge at balance: P/Q = R/S. Potentiometer: EMF is proportional to balance length, E1/E2 = L1/L2
Physics · Magnetism and alternating current
Electromagnetism
- Force on a wire = BIL sin θ, θ between the wire and the field; so 1 T = 1 N A−1 m−1
- Force on a moving charge = qvB sin θ, θ between the velocity and the field
- Charge moving at right angles to the field: radius r = mv/(qB); period T = 2πm/(qB), which does not depend on speed
- Field inside a long solenoid: B = μ0nI, where n = turns per metre and μ0 = 4π × 10−7 T m A−1
- Torque on a coil = NIAB cos α, α between the plane of the coil and the field (maximum NIAB when the plane is parallel to the field)
- Ammeter: shunt in parallel, Rs = IgRg/(I − Ig)
- Voltmeter: high resistance in series, Rh = (V/Ig) − Rg
Electromagnetic induction
- Flux = BA cos θ, θ between the field and the normal to the area; unit weber (Wb)
- Faraday's law: EMF = −N × (change in flux) ÷ (time taken) (ε = −N ΔΦ/Δt)
- Motional EMF of a rod moving at right angles to the field: ε = BLv
- Self-induction: ε = −L ΔI/Δt. Mutual induction: εs = −M ΔIp/Δt. L and M are in henry (H)
- Energy stored in an inductor = ½LI2
- AC generator: ε = NABω sin ωt, peak value NABω, with ω = 2πf
- Ideal transformer: Vs/Vp = Ns/Np = Ip/Is, so VpIp = VsIs
Alternating current
- rms value = peak value ÷ √2 ≈ 0.707 × peak (Vrms = V0/√2, Irms = I0/√2)
- Inductive reactance: XL = ωL = 2πfL, in Ω; it is proportional to f
- Capacitive reactance: XC = 1/(ωC) = 1/(2πfC), in Ω; it is proportional to 1/f
- Series RLC impedance: Z = √(R2 + (XL − XC)2), and Irms = Vrms/Z
- Phase angle: tan φ = (XL − XC)/R; average power = Vrms × Irms × cos φ
- Resonance: XL = XC, so ω0 = 1/√(LC) and f0 = 1/(2π√(LC))
- At series resonance Z = R (its smallest value), the current is a maximum and is in phase with the voltage
Physics · Solids and electronics
Physics of solids
- Stress = force ÷ area (σ = F/A), in Pa or N m−2; strain = extension ÷ original length (ε = ΔL/L), no unit
- Young's modulus = stress ÷ strain (Y = FL/(A × ΔL)), in Pa
- Extension ΔL = FL/(AY): proportional to length and to 1/diameter2
- Elastic energy stored = ½ × F × ΔL; energy per unit volume = ½ × stress × strain
- Crystalline: ordered, sharp melting point (metals, NaCl). Amorphous: no regular order, softens gradually (glass). Polymeric: long chains (plastics, rubber)
- Diamagnetic: weakly repelled. Paramagnetic: weakly attracted. Ferromagnetic: strongly attracted, becomes paramagnetic above the Curie temperature
- Soft magnetic material (soft iron): narrow hysteresis loop, small energy loss, used for transformer cores. Hard (steel): wide loop, used for permanent magnets
Electronics
- n-type: pentavalent impurity (P, As, Sb), majority carriers are electrons. p-type: trivalent impurity (B, Al, Ga, In), majority carriers are holes
- Forward bias: p side to the positive terminal, low resistance. Reverse bias: p side to the negative terminal, very high resistance
- Potential barrier: about 0.7 V for silicon and 0.3 V for germanium
- Half-wave rectifier: one diode, output frequency f. Full-wave bridge: four diodes, ripple frequency 2f
- Transistor: IE = IB + IC; current gain β = IC/IB
- Op-amp gain: inverting = −Rf/R1; non-inverting = 1 + (Rf/R1)
- Gates: AND gives 1 only if all inputs are 1; OR gives 1 if any input is 1; NOT inverts; NAND and NOR are AND and OR followed by NOT; XOR gives 1 when the inputs differ
Physics · Modern and nuclear physics
Dawn of modern physics
- Relativity: γ = 1/√(1 − v2/c2); time t = γt0, length L = L0/γ, mass m = γm0, energy E = mc2
- Photon energy = hf = hc/λ; a quick form is E (eV) = 1240 ÷ λ (nm)
- Photoelectric equation: hf = Φ + KEmax; KEmax = eV0 (V0 = stopping potential); threshold frequency f0 = Φ/h
- Compton shift: Δλ = (h/(m0c)) × (1 − cos θ), where h/(m0c) ≈ 2.4 pm for an electron
- de Broglie wavelength: λ = h/p = h/(mv); for a charge accelerated from rest through V, λ = h/√(2mqV)
- Pair production needs a photon of at least 2m0c2 = 1.02 MeV
- Uncertainty principle: Δx × Δp is at least of the order of h, so a smaller Δx means a larger Δp
Atomic spectra
- Bohr's condition: angular momentum mvr = nh/(2π)
- Hydrogen: radius rn = n2 × 0.053 nm; energy En = −13.6/n2 eV
- Photon energy = Eupper − Elower = hf = hc/λ
- Wavelength of a line: 1/λ = RH × (1/p2 − 1/n2) for a fall from level n to level p, RH = 1.097 × 107 m−1
- Series: Lyman (to n = 1) ultraviolet; Balmer (to n = 2) visible; Paschen (3), Brackett (4) and Pfund (5) infrared
- X-ray tube at voltage V: shortest wavelength λmin = hc/(eV), that is λmin (nm) = 1240 ÷ V (volts)
- Laser: population inversion in a metastable state, then stimulated emission gives photons of the same frequency, phase and direction
Nuclear physics
- In any nuclear equation the total A and the total Z are the same on both sides
- α decay: A falls by 4, Z falls by 2. β− decay: A unchanged, Z rises by 1. γ emission: A and Z unchanged
- Mass defect: Δm = Z × mp + (A − Z) × mn − mnucleus
- Binding energy = Δm × c2; with Δm in u, binding energy = Δm × 931 MeV
- Half-life: fraction left after n half-lives = (½)n, with n = t/T½; decay constant λ = 0.693/T½; activity = λN
- Ionising power: α > β > γ. Penetrating power: γ > β > α
- Cloud chamber tracks: α thick, straight and short; β thin and winding; γ faint and scattered
English · Vocabulary
Synonyms and antonyms
- Synonym = closest in meaning; antonym = most nearly opposite. Check which one is asked before you answer.
- Define the word in your own simple words first, then match the options to your definition.
- Prefixes: bene = good, mal = bad, in / im / un / dis = not, pre = before, post = after, re = again.
- Roots: chron = time, cred = believe, loqu = speak, luc / lum = light, ver = true, path = feeling.
- Decide the charge of the word (positive, negative or neutral). A synonym has the same charge; an antonym has the opposite charge.
- The answer is the same part of speech as the given word: adjective for adjective, verb for verb.
- Reject options that only belong to the same topic as the word but do not mean it.
Words in context
- Treat the word as a blank: predict your own word from the sentence before reading the options.
- The most familiar dictionary meaning is the usual trap. Test it; do not trust it.
- A colon, semicolon or 'since / because' clause usually explains the word.
- 'But', 'although', 'yet' and 'however' point to a meaning opposite to the other half of the sentence.
- Substitute each remaining option into the sentence; only one keeps the meaning.
- The answer must fit the grammar of the sentence as well as the sense.
English · Sentence completion
Sentence completion
- Contrast signals (blank opposes the clue): although, though, but, yet, however, despite, far from, rather than, surprisingly.
- Same-direction signals (blank agrees with the clue): and, because, since, so, therefore, indeed, moreover.
- A colon or semicolon usually introduces an explanation or example of the blank.
- 'So ______ that …' means the result after 'that' defines the blank.
- Predict your own word first; decide at least whether the blank is positive or negative.
- Two blanks: work out whether the two words agree or oppose each other, then eliminate one blank at a time.
- Read the finished sentence once in full. Choose by the logic of the sentence, not by the most impressive word.
English · Grammar and usage
Identifying errors
- The verb agrees with its real subject. Ignore phrases in between ('of …', 'together with …', 'as well as …'). 'The number of … is'; 'a number of … are'.
- After 'There is / are' and in inverted sentences, the subject comes after the verb: 'There are many reasons'.
- Tense follows the time words ('last year' needs the past). Past unreal condition: If + had + past participle, … would have + past participle.
- Pronoun case: I, he, she, we, they, who for subjects; me, him, her, us, them, whom for objects and after prepositions ('between you and me'). A pronoun also matches its noun in number.
- Parallel structure: items in a list, and both halves of 'not only … but also', 'both … and', 'either … or', take the same grammatical form.
- Comparison: comparative (-er / more) for two things, superlative (-est / most) for three or more; compare like with like ('than that of Lahore', 'than any other city').
- Fixed idioms: prefer X to Y; superior / inferior / senior / junior to; different from. Adverbs, not adjectives, describe verbs ('runs quietly').
Improving sentences
- A complete sentence has a subject and a finite verb and can stand alone. A clause beginning 'although', 'because' or 'when' cannot stand alone.
- Two complete sentences cannot be joined by a comma alone or by nothing. Use a full stop, a semicolon, a comma + and / but / so, or make one part a dependent clause.
- 'However' and 'therefore' are not joining words: write '; however,' or start a new sentence.
- An opening phrase with -ing or -ed must describe the subject that comes straight after the comma.
- A colon introduces a list or an explanation after a complete statement; a semicolon joins two complete sentences.
- its = belonging to it; it's = it is. One owner: factory's. Several owners: factories'.
- Cut repeated ideas: 'the reason is because', 'return back', 'and so therefore', 'collaborate together'.
English · Reading comprehension
Short passages
- Main idea: it must cover the whole passage. Reject an option about one detail (too narrow) or one that goes beyond the passage (too broad).
- Purpose: match the verb to what the author does: explain, describe, argue, warn, compare, or correct a common belief.
- After 'but', 'yet', 'however' or 'still' comes the author's own view; the first and last sentences often state the main point.
- Inference: a small, safe step that must be true if the passage is true. If you cannot point to the supporting line, it is a guess.
- Be wary of options with 'always', 'never', 'all', 'only' or 'proves' unless the passage is just as strong.
- Tone: read the judging words (adjectives, adverbs, verbs of praise or blame). Common answers: admiring, critical, cautious, concerned, objective.
- Word in the passage: substitute each option into the sentence and keep the one that preserves the meaning there.