Capacitors of 3 μF and 6 μF are connected in series across a 12 V battery. What is the charge on each capacitor?
- Series capacitance: C = (3 × 6)/(3 + 6) = 18/9 = 2 μF.
- Charge drawn from the battery: Q = CV = 2 μF × 12 V = 24 μC.
- Capacitors in series carry the same charge, so each one holds 24 μC (check: 24/3 + 24/6 = 8 V + 4 V = 12 V).
Answer: 24 μC on each capacitor.