Electronics

NUST NET (Engineering) · Physics · Solids and electronics. A short explanation of the idea, the rules to remember, the mistake to avoid, a worked example and practice questions with answers.

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The idea

A pure semiconductor such as silicon conducts poorly. Doping it with a tiny amount of impurity adds charge carriers: a group V atom gives a spare electron (n-type) and a group III atom leaves a hole (p-type). Both types stay electrically neutral overall.

Where p-type meets n-type, a depletion region with a potential barrier forms. Forward bias shrinks it and current flows; reverse bias widens it and almost no current flows. This one-way behaviour lets a diode turn AC into DC, which is rectification.

A transistor uses a small base current to control a much larger collector current. An op-amp is a very high gain amplifier whose working gain is set by two resistors. Logic gates give an output of 0 or 1 that depends on their inputs.

Rules to remember

Common mistake

Thinking an n-type semiconductor is negatively charged. It is neutral; the n only tells you that its majority carriers are electrons.

Worked example

An op-amp is used as an inverting amplifier with Rf = 50 kΩ and R1 = 10 kΩ. What is the output for an input of +0.30 V?

  1. Gain of an inverting amplifier = −Rf/R1 = −50/10 = −5.
  2. Output = gain × input = −5 × 0.30 = −1.5 V.
  3. The minus sign shows the output is inverted (180° out of phase with the input).

Answer: −1.5 V

Practice questions

Try each one, then open the answer.

1. When a p-n junction is forward biased,

  1. A
    the depletion region becomes wider
  2. B
    the depletion region becomes narrower and the barrier is reduced
  3. C
    only minority carriers cross the junction
  4. D
    the junction offers a very high resistance
Show answer

Answer: B. In forward bias the applied voltage opposes the junction's own potential barrier, so the depletion region narrows and majority carriers flow easily. In reverse bias it widens and only a tiny minority-carrier current flows.

2. Which logic gate gives an output of 1 only when both of its inputs are 0?

  1. A
    NAND
  2. B
    OR
  3. C
    AND
  4. D
    NOR
Show answer

Answer: D. NOR is OR followed by NOT: the OR output is 0 only when both inputs are 0, so the NOR output is 1 only then. A NAND gate gives 1 for three of the four input combinations.

3. The potential barrier across the depletion region of a silicon p-n junction is about

  1. A
    0.7 V
  2. B
    0.3 V
  3. C
    7 V
  4. D
    0.07 V
Show answer

Answer: A. For silicon the barrier is about 0.7 V (about 0.3 V for germanium). A forward bias larger than this is needed before an appreciable current flows.

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