The current in a coil of self-inductance 0.40 H falls steadily from 5.0 A to 2.0 A in 0.060 s. What is the size of the induced EMF, and which way does it act?
- Change in current: ΔI = 5.0 − 2.0 = 3.0 A.
- Rate of change: ΔI/Δt = 3.0/0.060 = 50 A s−1.
- EMF = L × ΔI/Δt = 0.40 × 50 = 20 V.
- By Lenz's law it opposes the fall, so it acts in the direction of the current and tries to keep it flowing.
Answer: 20 V, acting in the same direction as the current.