A grating has 400 lines per mm. Light of wavelength 650 nm is incident normally. At what angle is the second-order maximum? (sin 31.3° = 0.52)
- 400 lines per mm = 4.0 × 105 lines per m, so d = 1 ÷ (4.0 × 105) = 2.5 × 10−6 m.
- sin θ = nλ/d = (2 × 6.5 × 10−7) ÷ (2.5 × 10−6) = 1.3 × 10−6 ÷ 2.5 × 10−6 = 0.52.
- θ = sin−1(0.52) = 31.3°.
Answer: The second-order maximum is at 31.3° to the straight-through direction.