A wire of cross-sectional area 2.5 × 10−6 m2 carries a current of 2.0 A. The number density of free electrons is 1.0 × 1029 m−3 and e = 1.6 × 10−19 C. What is the drift speed?
- Rearrange I = Anvq to give v = I ÷ (Anq).
- Anq = 2.5 × 10−6 × 1.0 × 1029 × 1.6 × 10−19 = 4.0 × 104 C m−1.
- v = 2.0 ÷ (4.0 × 104) = 5.0 × 10−5 m s−1.
Answer: The drift speed is 5.0 × 10−5 m s−1 (0.050 mm s−1).