A skydiver of mass 80 kg is falling. At one instant the drag force on her is 300 N. What is her acceleration at that instant, and what is the drag force at terminal velocity? (g = 9.81 m s−2)
- Weight = mg = 80 × 9.81 = 784.8 N.
- Resultant force = weight − drag = 784.8 − 300 = 484.8 N downwards.
- Acceleration = resultant force ÷ mass = 484.8 ÷ 80 = 6.06 m s−2.
- At terminal velocity the resultant force is zero, so drag = weight = 785 N.
Answer: 6.1 m s−2 downwards; the drag at terminal velocity is about 785 N.