A student of mass 60 kg stands on a scale in a lift. The lift accelerates downwards at 1.5 m s−2. What is the contact force from the scale on the student? (g = 9.81 m s−2)
- Weight = mg = 60 × 9.81 = 588.6 N downwards.
- Taking downwards as positive, resultant force = weight − contact force = ma = 60 × 1.5 = 90 N.
- Contact force = 588.6 − 90 = 498.6 N.
Answer: About 500 N upwards, which is less than the student's weight.