Quadratics

AS Level Mathematics · Pure Mathematics 1. A short explanation of the idea, the rules to remember, the mistake to avoid, a worked example and practice questions with answers.

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The idea

A quadratic is an expression ax2 + bx + c. Most questions ask you to rewrite it, count its roots or solve with it.

Completing the square rewrites it as a(x + p)2 + q. This form shows the turning point of the graph at once. The discriminant b2 − 4ac tells you how many real roots there are without solving. Use it whenever a question says "tangent", "repeated root", "no real roots" or "does not meet".

For an inequality, find the critical values by solving the equation, then sketch the curve to see which region is wanted. For a line and a curve, substitute the linear equation into the other one. Some equations are quadratics in disguise, in x2, √x or tan x.

Rules to remember

Common mistake

When a is not 1, students subtract the wrong number. 2(x + 2)2 expands to 2x2 + 8x + 8, so you must take away 8, not 4. Always expand your answer to check it.

Worked example

Find the set of values of k for which x2 + kx + 9 = 0 has two distinct real roots.

  1. Two distinct real roots means b2 − 4ac > 0, with a = 1, b = k, c = 9.
  2. k2 − 4 × 1 × 9 > 0, so k2 − 36 > 0, which is (k − 6)(k + 6) > 0.
  3. Critical values are k = −6 and k = 6. The expression is positive outside them.

Answer: k < −6 or k > 6

Practice questions

Try each one, then open the answer.

1. Solve the inequality x2 − 5x − 14 ≤ 0.

  1. A
    x ≤ −2 or x ≥ 7
  2. B
    −2 ≤ x ≤ 7
  3. C
    −7 ≤ x ≤ 2
  4. D
    x ≤ 7
Show answer

Answer: B. Factorise: (x − 7)(x + 2) ≤ 0, critical values −2 and 7. The parabola opens upwards, so it is at or below the axis between the roots: −2 ≤ x ≤ 7.

2. The line y = 2x + c is a tangent to the curve y = x2 + 4x + 5. Find the value of c.

  1. A
    c = 1
  2. B
    c = 5
  3. C
    c = −4
  4. D
    c = 4
Show answer

Answer: D. Equate: x2 + 4x + 5 = 2x + c gives x2 + 2x + (5 − c) = 0. A tangent means one repeated root, so 4 − 4(5 − c) = 0, i.e. 5 − c = 1 and c = 4.

3. Find the coordinates of the maximum point of the curve y = 3 − 4x − x2.

  1. A
    (−2, 7)
  2. B
    (2, 7)
  3. C
    (−2, −1)
  4. D
    (−2, 3)
Show answer

Answer: A. y = −(x2 + 4x) + 3 = −[(x + 2)2 − 4] + 3 = 7 − (x + 2)2. The square is never negative, so the maximum value 7 occurs when x + 2 = 0, i.e. at (−2, 7).

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