1. A circle has a circumference of 18π centimeters. What is the area of the circle, in square centimeters?
- A9π
- B18π
- C81π
- D324π
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Answer: C. 2πr = 18π gives r = 9, so the area is π(9)2 = 81π. 324π uses the diameter, 18, as the radius.
By Team Megalecture · Updated 4 Nov 2026
92 exam-style questions on Math · Geometry and Trigonometry, each with the answer and a short explanation. Ten of them are below to try. The chapter test draws ten fresh questions each time and is marked the moment you finish, with your score by topic.
92 questions · 4 topics · 10 per test
Try each one, then open the answer. These ten stay the same; the test draws new ones every time.
Answer: C. 2πr = 18π gives r = 9, so the area is π(9)2 = 81π. 324π uses the diameter, 18, as the radius.
Answer: C. Completing the square gives (x − 4)2 + (y + 3)2 = 11 + 16 + 9 = 36, so the radius is 6. √11 uses the constant term before completing the square, 5 leaves out the 11, and 36 is r2.
Answer: C. V = πr2h = π(3)2(10) = 90π. 60π is the area of the curved side (2πrh), and 360π uses the diameter, 6, in place of the radius.
Answer: D. Let angle B = x°. Then angle A = 2x° and angle C = (2x + 20)°, so 5x + 20 = 180, x = 32, and angle C = 2(32) + 20 = 84°. 32° and 64° are angles B and A, and 60° comes from making C 20° less than A.
Answer: B. The sine of an angle equals the cosine of its complement, so 4x + (x + 10) = 90, giving x = 16. Setting 4x = x + 10 gives 10/3, and 20 comes from 4x + x − 10 = 90.
Answer: C. The sine of an angle equals the cosine of its complement, so 2x + (x + π/6) = π/2. Then 3x = π/3 and x = π/9. The value π/6 comes from forgetting that x also appears in the cosine.
Answer: D. sin A = BC/AB, so BC = 26 × 5/13 = 10. Then AC = √(262 − 102) = 24, and the perimeter is 10 + 24 + 26 = 60. 34 leaves out the hypotenuse, and 50 leaves out BC.
Answer: A. The sector is (2π/3) ÷ 2π = 1/3 of the circle, whose area is 36π, so the sector has area 12π. 24π leaves out the 1/2 in (1/2)r2θ, and 36π is the area of the whole circle.
Answer: C. The box has two faces of each size: 2(8 × 5) + 2(8 × 3) + 2(5 × 3) = 80 + 48 + 30 = 158. 120 is the volume, and 79 counts only one face of each size.
Answer: D. The circle is tangent to the x-axis, so its radius equals its center’s y-coordinate k, and its center is (6, k). Passing through (2, 2) gives 16 + (2 − k)2 = k2, so k = 5 and the equation is (x − 6)2 + (y − 5)2 = 25. The right side must be r2, not r.
92, each with the answer and a short explanation, across 4 topics: Area and volume, Lines, angles and triangles, Right triangles and trigonometry, Circles. Every chapter test draws ten of them, so you can take it many times.
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The moment you press Finish: your score, the right answer and an explanation for every question, and the ones you got wrong saved in My mistakes to retry.
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