A 5.0 Ω resistor is in series with a parallel pair of resistors, 20 Ω and 30 Ω. The supply is 8.5 V. What is the p.d. across the 5.0 Ω resistor?
- Parallel pair: R = (20 × 30) ÷ (20 + 30) = 600 ÷ 50 = 12 Ω.
- Total resistance = 5.0 + 12 = 17 Ω.
- Current from the supply = V ÷ R = 8.5 ÷ 17 = 0.50 A.
- p.d. across the 5.0 Ω resistor = I × R = 0.50 × 5.0 = 2.5 V.
Answer: 2.5 V (the other 6.0 V is across the parallel pair)