The solubility of a salt is 40 g per 100 g of water at 25 °C. A student stirs 25 g of the salt into 50 g of water at 25 °C and then filters. What mass of residue is collected?
- 50 g of water is half of 100 g, so the maximum mass that dissolves = 40 ÷ 2 = 20 g.
- 25 g is more than 20 g, so the solution is saturated and some salt does not dissolve.
- Mass of undissolved salt (the residue) = 25 − 20 = 5 g.
Answer: 5 g of residue; the filtrate is a saturated solution.