Ammonia, NH3, hydrogen sulfide, H2S, and sulfur dioxide, SO2, are released at the same moment at one end of a room. Which gas reaches the other end first? (H 1, N 14, O 16, S 32)
- Mr of NH3 = 14 + (3 × 1) = 17.
- Mr of H2S = (2 × 1) + 32 = 34.
- Mr of SO2 = 32 + (2 × 16) = 64.
- The gas with the smallest Mr has the fastest molecules at the same temperature, so it diffuses fastest.
Answer: Ammonia arrives first (Mr 17), then hydrogen sulfide (34), then sulfur dioxide (64).