Propane burns completely: C3H8 + 5O2 → 3CO2 + 4H2O. What volume of carbon dioxide, at room temperature and pressure, forms from 11 g of propane? (H 1, C 12; molar gas volume 24 dm3)
- Mr of C3H8 = (3 × 12) + (8 × 1) = 44.
- Moles of propane = 11 ÷ 44 = 0.25 mol.
- 1 mol of propane gives 3 mol of CO2, so moles of CO2 = 0.25 × 3 = 0.75 mol.
- Volume of CO2 = 0.75 × 24 = 18 dm3.
Answer: 18 dm3 of carbon dioxide