1. Given that log2 x = 5, find x.
- A32
- B10
- C25
- D2.5
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Answer: A. log2 x = 5 means 25 = x, so x = 32.
By Team Megalecture · Updated 4 Nov 2026
48 exam-style questions on Number and algebra, each with the answer and a short explanation. Ten of them are below to try. The chapter test draws ten fresh questions each time and is marked the moment you finish, with your score by topic.
48 questions · 5 topics · 10 per test
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Answer: A. log2 x = 5 means 25 = x, so x = 32.
Answer: B. Start from one side and transform it into the other: LHS = n2 + 2n + 1 − n2 + 2n − 1 = 4n = RHS. Starting from the result you want to prove assumes it is true.
Answer: B. (a + b)n has n + 1 terms, so power 5 needs six coefficients: 1, 5, 10, 10, 5, 1.
Answer: C. The term is 6C2(−3x)2 = 15 × 9x2 = 135x2. Squaring −3 gives +9; forgetting to square the 3 gives 45.
Answer: A. S25 = (25/2)(2 × 18 + 24 × 2) = 12.5 × 84 = 1050. 66 is only the number of seats in the last row.
Answer: B. u5 = S5 − S4 = (50 + 15) − (32 + 12) = 65 − 44 = 21. 65 is the sum of five terms, not the fifth term.
Answer: C. The general term is 4k − 1 (k = 1 gives 3). Solving 4k − 1 = 79 gives k = 20, so the upper limit is 20, not the last term 79.
Answer: A. u5 ÷ u2 = r3 = 8, so r = 2 and u1 = 12 ÷ 2 = 6. The ratio 8 covers three steps, not one.
Answer: A. An equation holds only for certain values (here x = 3). The symbol ≡ marks an identity: both sides are equal for every value of x.
Answer: C. 6C2 = 6!/(2! 4!) = (6 × 5)/2 = 15. 30 forgets to divide by 2!.
Start the chapter testAbout the IB Maths: Analysis and Approaches test
48, each with the answer and a short explanation, across 5 topics: SL1.2 Arithmetic sequences and series, SL1.3, SL1.4, SL1.8 Geometric sequences, series and financial applications, SL1.1, SL1.5, SL1.7 Standard form, exponents and logarithms, SL1.6 Simple deductive proof, SL1.9 The binomial theorem. Every chapter test draws ten of them, so you can take it many times.
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