IB Diploma Chemistry equations and key facts
Every chapter of IB Diploma Chemistry on one page: the 143 equations, definitions and facts to remember, in syllabus order. Use it for a last look before a test, then check yourself.
Structure 1: Models of the particulate nature of matter
The particulate nature of matter
- temperature in kelvin = temperature in °C + 273 (T = θ + 273)
- Average kinetic energy of the particles is proportional to the temperature in kelvin
- Endothermic changes (energy absorbed): melting, vaporization, sublimation
- Exothermic changes (energy released): freezing, condensation, deposition
- Filtration: insoluble solid from a liquid. Evaporation or crystallization: dissolved solid from its solution
- Distillation: a solvent from a solution, or liquids with different boiling points (fractional distillation)
- Solvent extraction: a solute that dissolves much better in one of two liquids that do not mix. Paper chromatography: small amounts of dissolved substances such as dyes
The nuclear atom
- Relative mass: proton 1, neutron 1, electron about 1/1836 (negligible)
- Relative charge: proton +1, neutron 0, electron −1
- number of neutrons = mass number − atomic number (A − Z)
- number of electrons = Z − charge on the ion (a 3+ ion has 3 fewer electrons, a 2− ion has 2 more)
- In a nuclear symbol the mass number A is the top number and the atomic number Z is the bottom number
- relative atomic mass = sum of (isotope mass × % abundance) ÷ 100
Electron configurations
- Hydrogen: transitions down to n = 1 give ultraviolet lines, to n = 2 visible lines, to n = 3 infrared lines
- maximum number of electrons in level n = 2n2 (2, 8, 18, 32)
- s sublevel: 1 orbital, 2 electrons. p: 3 orbitals, 6 electrons. d: 5 orbitals, 10 electrons. f: 7 orbitals, 14 electrons
- An s orbital is spherical; a p orbital is dumbbell-shaped
- Filling order up to Z = 36: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p
- Exceptions: Cr is [Ar] 3d5 4s1 and Cu is [Ar] 3d10 4s1
- When a d-block atom forms a positive ion, the 4s electrons are removed before the 3d electrons
Counting particles by mass: the mole
- number of particles = amount × Avogadro constant (N = n × L, L = 6.02 × 1023 mol−1)
- amount = mass ÷ molar mass (n = m ÷ M), with m in g and M in g mol−1
- concentration = amount ÷ volume (c = n ÷ V), with V in dm3; 1 dm3 = 1000 cm3
- Dilution: the amount of solute does not change, so c1 × V1 = c2 × V2
- Empirical formula: divide each mass or % by Ar, then divide every answer by the smallest
- molecular formula = empirical formula × (molar mass ÷ empirical formula mass)
- Avogadro's law: at the same temperature and pressure, equal volumes of gases contain equal amounts, so gas volumes react in the same ratio as the moles in the equation
Ideal gases
- pressure × volume = amount × gas constant × temperature (PV = nRT), R = 8.31 J K−1 mol−1
- Units for PV = nRT: P in Pa with V in m3, or P in kPa with V in dm3; T in K
- 1 dm3 = 1 × 10−3 m3 and 1 cm3 = 1 × 10−6 m3
- Combined gas law for a fixed amount: P1V1 ÷ T1 = P2V2 ÷ T2
- At constant T, volume is inversely proportional to pressure. At constant P, volume is proportional to T in kelvin
- At STP (273 K, 100 kPa) one mole of an ideal gas occupies 22.7 dm3: amount = volume ÷ 22.7
- molar mass = mass ÷ amount, with the amount found from n = PV ÷ RT
Structure 2: Models of bonding and structure
The ionic model
- Ion charges by group: group 1 is 1+, group 2 is 2+, group 13 is 3+, group 15 is 3−, group 16 is 2−, group 17 is 1−
- Polyatomic ions: NH4+, OH−, NO3−, HCO3−, CO32−, SO42−, PO43−
- In a formula the total positive charge equals the total negative charge; put brackets round a polyatomic ion that is used more than once
- Lattice enthalpy is larger when the ions have higher charges and smaller radii
- Ionic solids do not conduct (ions fixed in the lattice); they conduct when molten or dissolved in water (ions free to move)
- Many ionic compounds dissolve in polar solvents such as water but not in non-polar solvents such as hexane
The covalent model
- Bond strength: single < double < triple. Bond length: triple is shortest, single is longest
- 2 domains: linear, 180°. 3 domains: trigonal planar, 120°. 4 domains: tetrahedral, 109.5°
- 4 domains with 1 lone pair: trigonal pyramidal, about 107° (NH3). With 2 lone pairs: bent, about 105° (H2O)
- A bond is polar when the two atoms differ in electronegativity. A molecule is non-polar if its shape makes the bond dipoles cancel (CO2, CCl4)
- Strength of intermolecular forces: London (dispersion) < dipole–dipole < hydrogen bonding. London forces are stronger with more electrons; hydrogen bonding needs H bonded directly to N, O or F
- Diamond and SiO2: four bonds per C or Si, hard, non-conductors. Graphite and graphene: three bonds per C, delocalized electrons, conductors. C60 is molecular
- Rf = distance moved by the spot ÷ distance moved by the solvent front (never more than 1)
The metallic model
- Metallic bond: electrostatic attraction between a lattice of cations and delocalized electrons
- Stronger bonding with a higher cation charge, more delocalized electrons per atom and a smaller cation radius
- Electrical conductivity: delocalized electrons move when a potential difference is applied (the cations do not move)
- Thermal conductivity: delocalized electrons pass kinetic energy quickly through the lattice
- Across period 3, melting point rises: Na < Mg < Al (ions 1+, 2+, 3+ and getting smaller)
- Down group 1, melting point falls: the ions get larger, so the attraction for the delocalized electrons is weaker
From models to materials
- Δχ = higher electronegativity − lower electronegativity; average χ = (sum of the two values) ÷ 2
- Large Δχ (about 1.8 or more): ionic. Small Δχ with high average χ: covalent. Small Δχ with low average χ: metallic
- For an element Δχ = 0, so it lies on the base of the triangle: metals on the left, non-metals on the right
- The smaller the Δχ, the more covalent character an ionic compound has
- Alloys are mixtures, not compounds: no fixed formula, metallic bonding kept, so they still conduct
- Addition polymerization: the C=C bond of each alkene monomer opens and the monomers join; no other product forms
- Repeating unit of an addition polymer: the two C atoms of the C=C, now joined by a single bond, with one open bond at each end
Structure 3: Classification of matter
The periodic table: classification of elements
- Across a period: atomic radius decreases; first ionization energy and electronegativity increase. Down a group: radius increases; ionization energy and electronegativity decrease
- Ions with the same number of electrons: the more protons, the smaller the ion (N3− > O2− > F− > Na+)
- First electron affinity: X(g) + e− → X−(g). First ionization energy: X(g) → X+(g) + e−
- Group 1 with water: 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g); more vigorous down the group
- A halogen higher in group 17 displaces a lower one from its halide: Cl2(aq) + 2Br−(aq) → 2Cl−(aq) + Br2(aq)
- Metal oxides are basic: Na2O + H2O → 2NaOH. Non-metal oxides are acidic: SO3 + H2O → H2SO4; CO2 + H2O ⇌ H2CO3. Al2O3 is amphoteric
- Oxidation states add up to zero in a compound and to the charge in an ion; O is usually −2 and H is usually +1
Functional groups: classification of organic compounds
- Groups: halogeno –X, hydroxyl –OH, carbonyl C=O, carboxyl –COOH, alkoxy –OR, amino –NH2, amido –CONH2, ester –COO–, phenyl –C6H5
- Chain names: meth 1, eth 2, prop 3, but 4, pent 5, hex 6 carbon atoms
- Naming: find the longest carbon chain, then number it so that the functional group and branches get the lowest numbers
- Alcohols and halogenoalkanes: primary, secondary or tertiary = 1, 2 or 3 carbon atoms bonded to the carbon that carries the –OH or halogen
- Amines: primary, secondary or tertiary = 1, 2 or 3 carbon atoms bonded to the nitrogen atom
- Isomers: chain (different carbon skeleton), position (same group in a different place), functional group (different group, such as alcohol and ether, or aldehyde and ketone)
- Compounds that can form hydrogen bonds (alcohols, carboxylic acids) boil at higher temperatures than alkanes of similar molar mass
Reactivity 1: What drives chemical reactions?
Measuring enthalpy changes
- heat = mass of water or solution × specific heat capacity × temperature change (Q = mcΔT), with c = 4.18 J g−1 K−1
- enthalpy change = −heat ÷ moles reacted (ΔH = −Q ÷ n), in kJ mol−1, so change Q from J to kJ first
- Temperature rises: exothermic, ΔH negative. Temperature falls: endothermic, ΔH positive
- On an energy profile: ΔH = enthalpy of products − enthalpy of reactants
- activation energy (Ea) = enthalpy of the transition state − enthalpy of the reactants
- Lower enthalpy means more stable
- Standard conditions for ΔH⦵: 100 kPa, usually 298 K, solutions at 1 mol dm−3
Energy cycles in reactions
- ΔH = total bond enthalpy of bonds broken − total bond enthalpy of bonds formed
- Bond breaking is endothermic (+). Bond forming is exothermic (−)
- Count every bond: CH4 has four C–H, CO2 has two C=O, H2O has two O–H, and multiply by the coefficients
- Bond enthalpies are averages and apply to gases only, so the result differs from the experimental value
- Hess's law: ΔH is the same for every route from the same reactants to the same products
- Reverse an equation: change the sign of ΔH. Multiply an equation: multiply ΔH by the same number
Energy from fuels
- Complete combustion: C3H8 + 5O2 → 3CO2 + 4H2O
- Incomplete combustion: 2C3H8 + 7O2 → 6CO + 8H2O
- Metals and non-metals: 2Mg + O2 → 2MgO and S + O2 → SO2
- Carbon monoxide binds to haemoglobin, so the blood carries less oxygen
- Greenhouse gases absorb infrared radiation given out by the Earth's surface and send some of it back
- Hydrogen fuel cell, acidic electrolyte. Anode: H2 → 2H+ + 2e−. Cathode: O2 + 4H+ + 4e− → 2H2O
- Hydrogen fuel cell overall: 2H2 + O2 → 2H2O
Reactivity 2: How much, how fast and how far?
How much? The amount of chemical change
- moles = mass ÷ molar mass (n = m ÷ M)
- moles = concentration × volume in dm3 (n = cV), and 1 dm3 = 1000 cm3
- moles of gas = volume ÷ molar volume; molar volume at STP = 22.7 dm3 mol−1
- Limiting reactant: divide the moles of each reactant by its coefficient; the smallest result is limiting
- percentage yield = (actual yield ÷ theoretical yield) × 100
- atom economy = (molar mass of desired product ÷ total molar mass of all reactants) × 100, using the coefficients
- Ionic equation: leave out spectator ions, e.g. Ag+(aq) + Cl−(aq) → AgCl(s)
How fast? The rate of chemical change
- rate = change in concentration ÷ time taken, in mol dm−3 s−1
- Rate at a given time = gradient of the tangent to the curve at that time
- Higher concentration, higher gas pressure or larger surface area: more frequent collisions
- Higher temperature: collisions are slightly more frequent, but mainly a much larger proportion have energy ≥ Ea
- Maxwell–Boltzmann curve: starts at the origin, never touches the energy axis again, and the area under it is the total number of particles
- At a higher temperature the peak is lower and further right; the area stays the same
- A catalyst lowers Ea but does not change ΔH or the energy distribution, and it is not used up
How far? The extent of chemical change
- For aA + bB ⇌ cC + dD: Kc = ([C]c × [D]d) ÷ ([A]a × [B]b)
- K much greater than 1: equilibrium lies to the right. K much less than 1: it lies to the left
- Add a reactant or remove a product: position shifts right. K is unchanged
- Increase the pressure: position shifts to the side with fewer moles of gas. K is unchanged
- Increase the temperature: position shifts in the endothermic direction, and K changes
- Exothermic forward reaction: K falls as temperature rises. Endothermic forward reaction: K rises
- Catalyst: equilibrium is reached sooner; position and K stay the same
Reactivity 3: What are the mechanisms of chemical change?
Proton transfer reactions
- pH = −log10[H+] and [H+] = 10−pH, with [H+] in mol dm−3
- Kw = [H+][OH−] = 1.00 × 10−14 at 298 K
- Conjugate pair: acid and base differ by one H+, e.g. NH4+ / NH3 and H2O / OH−
- Strong acids: HCl, HNO3, H2SO4. Weak acids: ethanoic acid, carbonic acid
- Strong bases: NaOH, KOH. Weak base: NH3
- acid + base → salt + water; acid + carbonate or hydrogencarbonate → salt + water + CO2
- Strong acid with strong base: the pH curve has a steep vertical section with the equivalence point at pH 7
Electron transfer reactions
- Oxidation Is Loss of electrons, Reduction Is Gain (OIL RIG)
- Half-equation in acid: balance the main atoms, add H2O for O, add H+ for H, then add e− to balance the charge
- In every cell, oxidation is at the anode and reduction is at the cathode
- Voltaic cell: the anode is negative, electrons flow through the wire from anode to cathode, chemical energy → electrical energy
- Electrolytic cell: the anode is positive. Molten salt: metal forms at the cathode, non-metal at the anode
- Oxidation with acidified K2Cr2O7: primary alcohol → aldehyde (distil) → carboxylic acid (reflux); secondary alcohol → ketone; tertiary alcohol: no reaction
- Reduction reverses this: aldehyde or carboxylic acid → primary alcohol, ketone → secondary alcohol. Alkene + H2 → alkane
Electron sharing reactions
- Initiation (UV light): Cl2 → 2Cl•
- Propagation 1: CH4 + Cl• → CH3• + HCl
- Propagation 2: CH3• + Cl2 → CH3Cl + Cl•
- Termination: two radicals join, e.g. 2Cl• → Cl2, CH3• + Cl• → CH3Cl, 2CH3• → C2H6
- Overall: CH4 + Cl2 → CH3Cl + HCl
- Excess halogen gives further substitution: CH2Cl2, CHCl3, CCl4
- Count radicals to name a step: none → radicals is initiation; one → one is propagation; two → none is termination
Electron-pair sharing reactions
- Nucleophiles have a lone pair or a negative charge: OH−, H2O, NH3, CN−, Cl−
- Electrophiles have a positive or partial positive charge: H+, Hδ+ in HBr, Brδ+ in a polarized Br2 molecule
- Nucleophilic substitution: CH3CH2Br + OH− → CH3CH2OH + Br− (the leaving group is the halide ion)
- Alkene + halogen → dihalogenoalkane: C2H4 + Br2 → CH2BrCH2Br
- Alkene + hydrogen halide → halogenoalkane: C2H4 + HBr → CH3CH2Br
- Alkene + steam, with an acid catalyst → alcohol: C2H4 + H2O → CH3CH2OH
- Bromine water turns from orange to colourless with an alkene