1. One root of x2 − kx + 18 = 0 is 3. The value of k is
- A6
- B9
- C15
- D27
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Answer: B. The roots multiply to 18, so the other root is 6, and k = sum of roots = 3 + 6 = 9. 6 is the other root, not k.
By Team Megalecture · Updated 13 Nov 2026
100 exam-style questions on Quantitative · Algebra, each with the answer and a short explanation. Ten of them are below to try. The chapter test draws ten fresh questions each time and is marked the moment you finish, with your score by topic.
100 questions · 5 topics · 10 per test
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Answer: B. The roots multiply to 18, so the other root is 6, and k = sum of roots = 3 + 6 = 9. 6 is the other root, not k.
Answer: C. f−1(8) is the x with 5x − 7 = 8, so 5x = 15 and x = 3. The value 33 is f(8), not the inverse.
Answer: B. x2 − (sum)x + (product) = 0 with sum −2 and product −15 gives x2 + 2x − 15 = 0. Forgetting the minus in front of the sum gives x2 − 2x − 15.
Answer: D. Difference of two squares: x2 − (7y)2 = (x − 7y)(x + 7y). (x − 7y)2 would give a middle term −14xy.
Answer: D. Discriminant = (−3)2 − 4 × 2 × 5 = 9 − 40 = −31 < 0, so there are no real roots.
Answer: B. h = 0 gives 5t(4 − t) = 0, so t = 0 (the throw) or t = 4 s. 2 s is when it reaches its highest point.
Answer: A. 4m + 250 = 1,090, so 4m = 840 and m = 210. 840 forgets to divide by 4; 335 adds the 250 instead of subtracting it.
Answer: A. (2x + 1)(x + 3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3. (2x + 3)(x + 1) gives a middle term of only 5x.
Answer: C. y = 13 − 2x, so 4x − 39 + 6x = 1, 10x = 40, x = 4 and y = 13 − 8 = 5.
Answer: B. P = 120 × 15 − 800 = 1,800 − 800 = Rs 1,000. Rs 1,800 forgets to subtract the fixed 800.
Start the chapter testAbout the NUST NET Quantitative Maths test
100, each with the answer and a short explanation, across 5 topics: Algebraic expressions and identities, Linear and simultaneous equations, Quadratic equations, Inequalities and absolute value, Functions and graphs. Every chapter test draws ten of them, so you can take it many times.
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