A box of weight 50 N rests on a slope at 20° to the horizontal. What are the components of its weight along the slope and at right angles to the slope? (sin 20° = 0.342, cos 20° = 0.940)
- The angle between the weight and the line at right angles to the slope is 20°, the same as the angle of the slope.
- Component at right angles to the slope (next to the angle) = 50 × cos 20° = 50 × 0.940 = 47 N.
- Component along the slope (opposite the angle) = 50 × sin 20° = 50 × 0.342 = 17.1 N.
Answer: 17 N down the slope and 47 N at right angles to the slope.