A microphone and oscilloscope display a sound wave. The time-base is 0.50 ms per division and two complete cycles take up 8.0 divisions. The speed of sound is 330 m s−1. What is the wavelength?
- One cycle = 8.0 ÷ 2 = 4.0 divisions, so period T = 4.0 × 0.50 ms = 2.0 ms = 2.0 × 10−3 s
- Frequency f = 1 ÷ T = 1 ÷ (2.0 × 10−3) = 500 Hz
- Wavelength λ = v ÷ f = 330 ÷ 500 = 0.66 m
Answer: 0.66 m