Plane-polarised light of intensity 60 W m−2 passes through two polarising filters. The first has its axis at 45° to the plane of polarisation. The second has its axis at 90° to the original plane of polarisation. What is the final intensity? (cos 45° = 0.707)
- After the first filter: I1 = 60 × cos245° = 60 × 0.50 = 30 W m−2
- This light is now polarised along the first axis, so its angle to the second axis is 90° − 45° = 45°
- After the second filter: I2 = 30 × cos245° = 30 × 0.50 = 15 W m−2
Answer: 15 W m−2