A uniform rod of weight 40 N and length 1.2 m is hinged to a wall at one end. It is held horizontal by a string fixed to its other end. The string makes an angle of 30° with the rod. What is the tension in the string? (sin 30° = 0.500)
- Take moments about the hinge, so the force at the hinge has no moment.
- Clockwise moment of the weight = 40 × 0.60 = 24 N m (the weight acts at the midpoint).
- Anticlockwise moment of the tension = T × sin 30° × 1.2 = 0.60T.
- 0.60T = 24, so T = 24 ÷ 0.60 = 40 N.
Answer: 40 N