0.0200 mol of strontium nitrate, Sr(NO3)2, is heated until it has decomposed completely. What is the total volume of gas produced, measured at room conditions (24.0 dm3 mol−1)?
- Equation: 2Sr(NO3)2 → 2SrO + 4NO2 + O2.
- 2 mol of nitrate give 4 + 1 = 5 mol of gas, so 1 mol gives 2.5 mol of gas.
- Moles of gas = 0.0200 × 2.5 = 0.0500 mol.
- Volume = 0.0500 × 24.0 = 1.20 dm3.
Answer: 1.20 dm3 of gas (NO2 and O2 together).