On a graph of reactant concentration against time, the tangent drawn at 40 s passes through the points (0 s, 0.60 mol dm−3) and (100 s, 0.10 mol dm−3). What is the rate of reaction at 40 s?
- Rate at 40 s = size of the gradient of the tangent.
- Change in concentration = 0.60 − 0.10 = 0.50 mol dm−3; change in time = 100 − 0 = 100 s.
- Rate = 0.50 ÷ 100 = 5.0 × 10−3 mol dm−3 s−1.
Answer: 5.0 × 10−3 mol dm−3 s−1