An oxide of a Period 3 element is a white solid that reacts violently with water to give a solution of pH about 1. The element has oxidation number +5 in the oxide. Identify the oxide and write the equation for its reaction with water.
- A strongly acidic solution means a covalent oxide of a non-metal, so it is an oxide of phosphorus or sulfur.
- Oxidation number +5 means five outer-shell electrons, which is phosphorus (sulfur gives +4 or +6).
- Check in P4O10: 4x + 10 × (−2) = 0, so x = +5.
Answer: The oxide is P4O10: P4O10 + 6H2O → 4H3PO4.