A compound containing only carbon, hydrogen and one type of halogen has molecular ion peaks at m/e 78 and 80 with heights in the ratio 3 : 1. The peak at 78 has abundance 60.0 and the peak at 79 has abundance 2.0. Find the molecular formula.
- M and [M + 2] in the ratio 3 : 1 show one chlorine atom, and the peak at 78 contains 35Cl.
- n = (100 × 2.0) ÷ (1.1 × 60.0) = 200 ÷ 66 = 3.03, so there are 3 carbon atoms.
- Mass left for hydrogen = 78 − 35 − (3 × 12) = 7, so there are 7 hydrogen atoms.
Answer: C3H7Cl.