A reaction has ΔH = −40 kJ mol−1 and a forward activation energy of 120 kJ mol−1. A catalyst lowers the forward activation energy to 75 kJ mol−1. What is the activation energy of the reverse reaction with the catalyst?
- The reaction is exothermic, so the products lie 40 kJ mol−1 below the reactants.
- The reverse reaction must climb from the products to the same peak: reverse EA = forward EA + 40.
- With the catalyst: reverse EA = 75 + 40 = 115 kJ mol−1.
- Check: without the catalyst it is 120 + 40 = 160, so both directions are lowered by 45 kJ mol−1.
Answer: 115 kJ mol−1