A hydrocarbon contains 85.7% carbon and 14.3% hydrogen by mass. Its Mr is 56. What is its molecular formula? (Ar: C 12.0, H 1.0)
- Moles: C = 85.7 ÷ 12.0 = 7.14; H = 14.3 ÷ 1.0 = 14.3.
- Divide by the smallest: C = 1, H = 14.3 ÷ 7.14 = 2.00. Empirical formula is CH2.
- Empirical formula mass = 12.0 + 2.0 = 14.0, and 56 ÷ 14.0 = 4.
- Molecular formula = 4 × CH2.
Answer: C4H8.