Carboxylic acids

AS Level Chemistry · Carboxylic acids and derivatives. A short explanation of the idea, the rules to remember, the mistake to avoid, a worked example and practice questions with answers.

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The idea

Carboxylic acids contain the –COOH group. They are weak acids: in water only a small fraction of the molecules ionise, RCOOH ⇌ RCOO− + H+. They still show all the usual acid reactions and form salts called carboxylates, such as sodium ethanoate.

They are much stronger acids than alcohols. A carboxylic acid gives carbon dioxide with a carbonate, and an alcohol does not. This is the simple test for –COOH.

Carboxylic acids are made by oxidising a primary alcohol or an aldehyde under reflux, or by hydrolysing a nitrile or an ester. They react with alcohols to form esters, and LiAlH4 reduces them to primary alcohols.

Rules to remember

Common mistake

After hydrolysis with dilute alkali, students write the carboxylic acid as the product. In alkali the product is the carboxylate salt, for example sodium ethanoate; the acid forms only after the mixture is acidified.

Worked example

0.0300 mol of ethanoic acid reacts completely with excess magnesium. What volume of hydrogen forms at room conditions? (1 mol of gas occupies 24.0 dm3.)

  1. Equation: 2CH3COOH + Mg → (CH3COO)2Mg + H2, so 2 mol of acid give 1 mol of H2.
  2. Moles of H2 = 0.0300 ÷ 2 = 0.0150 mol.
  3. Volume = 0.0150 × 24.0 = 0.360 dm3.

Answer: 0.360 dm3 of hydrogen.

Practice questions

Try each one, then open the answer.

1. Methyl propanoate is heated under reflux with aqueous sodium hydroxide, and the mixture is then acidified. Which carboxylic acid is obtained?

  1. A
    methanoic acid
  2. B
    ethanoic acid
  3. C
    propanoic acid
  4. D
    butanoic acid
Show answer

Answer: C. Alkaline hydrolysis gives sodium propanoate and methanol; adding acid converts the propanoate ion into propanoic acid. The -oate part of the ester name identifies the acid.

2. Propanenitrile is heated under reflux with dilute hydrochloric acid. What is the organic product?

  1. A
    propanoic acid
  2. B
    ethanoic acid
  3. C
    propylamine
  4. D
    propanal
Show answer

Answer: A. Acid hydrolysis converts the –CN group to –COOH with no change in carbon number: CH3CH2CN + 2H2O + H+ → CH3CH2COOH + NH4+. Three carbons in, three carbons out.

3. Which reagents and conditions convert ethanol into ethanoic acid?

  1. A
    acidified K2Cr2O7, heat and distil off the product immediately
  2. B
    excess acidified K2Cr2O7, heat under reflux
  3. C
    NaBH4 in water
  4. D
    concentrated H2SO4 at 170 °C
Show answer

Answer: B. Refluxing with excess oxidising agent keeps the ethanal intermediate in the flask until it is fully oxidised to ethanoic acid. Distilling immediately collects ethanal instead.

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