An alcohol C4H10O turns warm acidified K2Cr2O7 from orange to green and gives a yellow precipitate with alkaline aqueous iodine. Identify it.
- It is oxidised, so it is not the tertiary alcohol 2-methylpropan-2-ol.
- The yellow precipitate shows a CH3CH(OH)– group.
- Butan-1-ol and 2-methylpropan-1-ol have –CH2OH groups, so they give no precipitate.
- Only CH3CH(OH)CH2CH3 has the group needed.
Answer: Butan-2-ol, a secondary alcohol.